a = 'nihao'
b = 100
c = 199.32
print(f"{a:>010}")
print(f'{a:>10}')
print(f'{c:010.2f}')

i =100
print(i)
i+=1
print(i)

a = 100
b = 200
a,b = b,a
print(a)
print(b)


for i in range(0,5,1):
    if i == 2:
        print('找到2')
        # continue
        # break
        raise Exception
        
else:
    print('循环全部执行')